The negation of the Boolean expression x | vedclass

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Question

$p \leftrightarrow q \equiv( p \rightarrow q ) \wedge( q \rightarrow p )$

$x \leftrightarrow \sim y \equiv( x \rightarrow \sim y ) \wedge(\sim y \r

Vedclass · Accepted Answer

$(x \wedge y) \vee(\sim x \wedge \sim y)$

Vedclass · Answer

$p \leftrightarrow q \equiv( p \rightarrow q ) \wedge( q \rightarrow p )$

$x \leftrightarrow \sim y \equiv( x \rightarrow \sim y ) \wedge(\sim y \rightarrow x )$

$\because( p \rightarrow q \equiv \sim p \vee q )$

$x \leftrightarrow \sim y \equiv(\sim x \vee \sim y ) \wedge( y \vee x )$

$\sim( x \leftrightarrow \sim y ) \equiv( x \wedge y ) \vee(\sim x \wedge \sim y )$

The negation of the Boolean expression $x \leftrightarrow \sim y$ is equivalent to

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$( S 1)( p \Rightarrow q ) \vee( p \wedge(\sim q ))$ is a tautology $( S 2)((\sim p ) \Rightarrow(\sim q )) \wedge((\sim p ) \vee q )$ is a Contradiction. Then